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3^x=(1/9)^3
We move all terms to the left:
3^x-((1/9)^3)=0
We add all the numbers together, and all the variables
3^x-((+1/9)^3)=0
We multiply all the terms by the denominator
3^x*9)^3)-((+1=0
Wy multiply elements
27x^2+1=0
a = 27; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·27·1
Δ = -108
Delta is less than zero, so there is no solution for the equation
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